Solve by the method of substitution. Aftab tells his daughter,"Seven years ago,$I$ was seven times as old as you were then. Also,three years from now,$I$ shall be three times as old as you will be." Represent this situation algebraically.

(N/A) Let $s$ and $t$ be the current ages (in years) of Aftab and his daughter,respectively.
According to the first condition,seven years ago:
$(s - 7) = 7(t - 7)$
$s - 7 = 7t - 49$
$s - 7t = -42$ $...(1)$
According to the second condition,three years from now:
$(s + 3) = 3(t + 3)$
$s + 3 = 3t + 9$
$s - 3t = 6$ $...(2)$
From Equation $(2)$,we get $s = 3t + 6$.
Substituting this value of $s$ into Equation $(1)$:
$(3t + 6) - 7t = -42$
$-4t + 6 = -42$
$-4t = -48$
$t = 12$
Now,substitute $t = 12$ into $s = 3t + 6$:
$s = 3(12) + 6 = 36 + 6 = 42$
Thus,the current age of Aftab is $42$ years and his daughter is $12$ years old.